Question

what is the energy associated with photon of wavelength 4000A​

Answer 1

Answer:

Explanation:

E

=

h

c

λ

E

=

h

c

λ

=

6.626

×

10

−

34

J s

×

3

×

10

8

m/s

4000

×

10

−

10

m

E

=

4.97

×

10

−

19

Answer 2

Answer:

Given, λ=4000

A

o

=4000×10

−10

m

=4×10

−7

m

We know that,

E=hv

But, c=v=v=

λ

c

∴E=

λ

c

[∴h=6.6×10

−34

]

E=

4×10

−7

6.6×10

−34

×3×10

8

J and C=3×10

4

E=4.95×10

−19

J

Explanation:

hope it's help you