what is the energy in electron -volt of a photo electron moving with velocity 2x10^7 m/s. given mass of electron 9.1x10^-31kg.
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Equation of energy of electron
E=eV₀.......where E is energy,
e is the charge on the electron,
V₀ is stopping potential.
Therefore,E=1.6*10^-19×2*10^7
=3.2*10^-12
E=eV₀.......where E is energy,
e is the charge on the electron,
V₀ is stopping potential.
Therefore,E=1.6*10^-19×2*10^7
=3.2*10^-12
Arunav5:
1.6x10^-19coulomb
ohk
1/4π∈o x pcostheta/ (r^2-a^cos^theta)
can this formula be used
sry its r^2-a^2 cos^2theta
probably noo..!!
but what about the mass 9.1x10^-31
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energy of a photon E=ev where e=charge of electron=1.6 x10*-19 v=2 x10*7m/s then E= 1.6 x 2 x10*-19 x10*7=3.2 x10*-12j
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