Chemistry, asked by scs550130, 25 days ago

What is the energy of each of the following photons in kilojoules per mole a) v=3.79 1011s (b) v=5.45 x 10's (c)=4.11 x 105 m​

Answers

Answered by Manthanchinchekar007
2

Answer:

c , = νλ ∴ λ λ

ν ν

min max

max min

c c

= ; =

AM λ

8

min 3

3 x 10 m / s

= = 188 m

1600 x 10 Hz λ

8

max 3

3 x 10

= = 566 m

530 x 10

FM λ

8

min 6

3 x 10

= = 2.78 m

108 x 10 λ

8

max 6

3 x 10

= = 3.41 m

8

Explanation:

Answered by adventureisland
0

The photons in kilojoules per mole 4.79*10^{-7}\frac{KJ}{mol photom}.

Explanation:

E=nv

E=(6.626*10^{-34}J.S)(1.20*10^{6}s^{-1})

E=7.95*10^{-28}\frac{J}{photoms}

E=\frac{7.95*10^{-28}J}{1photon} \frac{1KJ}{10^{3}J}\frac{6.02*10^{23}photon}{1molphoton}

E=4.79*10^{-7}\frac{KJ}{mol photom}

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