Question

What is the enthalpy change for this reaction and is it endothermic or  exothermic?  H2(g)+I2(g)→2HI(g), given; H-H bond energy: 436 kJ/mol, I-I bond  energy: 151 kJ/mol, H-I bond energy: 297 kJ/mol.  ​

Answer 1

Answer:

Because enthalpy is a state function, the sum of the enthalpies of the individual steps is equal to the enthalpy change for the overall reaction. Calculate the lattice energy for CaH 2 using the following information. (E EA for H = - 72.8 kJ/mol; E i1 for Ca=590 kJ/mol; E i2 for Ca =1145 kJ/mol; heat of subm for Ca =178 kJ/mol; bond dissociation energy for H 2 =436 kJ/mol; net energy for the formation of CaH 2 from its elements =-186 kJ mol.

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