Math, asked by bharatbhushangiri4au, 9 months ago

What is the equation of the ellipse with foci (1,1) and (-1,-1) and length the of major axis
is 4.​

Answers

Answered by sainathsankar
2

Answer: 0

Step-by-step explanation:

Foci (−1,1) & (1,1) of ellipse.

Passes through (0,0)

Centre of ellipse =(0,1)  midpoints of the line between focus

value b=1

ae=1

a  

1−  

a  

2

 

b  

2

 

​  

 

​  

⇒a  

1−  

a  

2

 

1

​  

 

​  

=1⇒  

a  

2

−1

​  

=1

a=  

2

​  

 

centre is shifted to (0,1).

(  

2

​  

)  

2

 

(x−0)  

2

 

​  

+  

1

(y−1)  

2

 

​  

=1

2

x  

2

 

​  

+  

1

y  

2

+1−2y

​  

=1

x  

2

+2y  

2

+2−4y=2

x  

2

+2y  

2

−4y=0

Answered by nidhiakara
0

Answer:

Step-by-step explanation:

        sist b/w foci is 2ae = 2√2 i.e ae = √2

                           u gave that a = 4 then e = 1/2√2

                                  we know that centre is mid pt of focii

                  then centre is (0,0) and b²= a²(1 - e²)

                             u get b² = 14

     then equation of ellipse is x²/16 + y²/14 = 1

    hope u get it n let me know.............

Similar questions