Question

What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?
y = –1/3x + 5 y = –1/3x + 3
y = 3x + 2 y = 3x − 5

Answer 1

Step-by-step explanation:

Slope of line 3x+y=3 is m=−3

Hence slope of perpendicular line is m

′

=

3

1

Therefore equation of perpendicular line is

(y−2)=

3

1

(x−2)

⇒3y−6=x−2

⇒x−3y+4=0

So y-intercept is y=

3

4