Question

What is the equation of the line that is perpendicular to the line and passes through the point (15,-5)?

Answer 1

Slope of the line y = x + 10 is 1. So, any straight line perpendicular to this must be having slope of (-1).

Let, the line be y = - x + b and it passes through (15, -5).

So, 15 = 5 + b

b = 10.

So, equation of that line: y = -x + 10

Or, x + y = 10.

Y-intercept of the line = 10 units.