Question

What is the equation of the line that passes through the points (-5, 0) and (7, 8)?

Answer 1

Answer:

y=2/3x+10/3

Step-by-step explanation:

Answer 2

We know that :-

$\rm Equation \: of \: line \: passing \: through \: points \: (x_1 , y_1) \: and \: (x_2 , y_2) :$

$\tt \longrightarrow y - y_1 = x-x_1\bigg( \dfrac{y_2-y_1}{ x_2-x_1} \bigg )$

$\rm \rightarrow \: here \: \bigg( \dfrac{y_2-y_1}{ x_2-x_1} \bigg ) is \: slope \: of \: line.$

Now , we have to find out the equation of the line that passes through the points (-5, 0) and (7, 8).

$\tt \implies y - 0 = (x + 5)\bigg( \dfrac{8-0}{ 7 + 5} \bigg ) \\ \\ \\ \tt \implies y = (x + 5)\bigg( \dfrac{8}{ 12} \bigg )\\ \\ \\ \tt \implies y = (x + 5)\bigg( \dfrac{2}{ 3} \bigg )\\ \\ \\ \tt \implies 3y = (x + 5)2\\ \\ \\ \tt \implies 3y = 2x + 10\\ \\ \\ \tt \implies 3y - 2x - 10 = 0$

The equation of the line that passes through the points (-5, 0) and (7, 8) :-

3y-2x-10=0