Question

What is the equation of the straight line perpendicular to ax +by+c=0?

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Answer 1

Prove that the equation of a line perpendicular to a given line ax + by + c = 0 is bx - ay + λ = 0, where λ is a constant. Let m1 be the slope of the given line ax + by + c = 0 and m2 be the slope of a line perpendicular to the given line.

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Answer 2

Step-by-step explanation:

ax+by+c=0

this is a straight line in form of y=mx+c

y=(-a/b)x-c/b

slope of this line=-a/b

we know the product of slope of line which are perpendicular to each other is -1

m1×m2=-1

slope of first line is -a/b

hence slope of second line

=-a/b×m2=-1

m2= b/a

hence the equation is

y=(b/a)x+z

where z can be any constant....