Question

What is the equation of the tangent to the curve x3+y3+3x−6y=0 at the coordinate (1,2)?

Answer 1

Heyaa☺

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Given,equation

Curve =》X^3+Y^3+3X-6Y = 0

(1,2) X = 1 ; Y = 2

1 + 8 + 3 - 12 = 0

9 + (-9) = 0

=》0.

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