Math, asked by rnopn, 1 year ago

What is the escape velocity of the moon??

Answers

Answered by eshan29118
1

The escape velocity on the surface of the moon is 2.38km/sec

Answered by nilesh102
3

\huge \underline\red{Answer:-} \\  \\   \underline\red{escape \: velocity \: :-} \:  \ \: velocity \: which \: is \:  \\ needed \: by \: any \: object \: (body)  \: to \:  escape \:  \\ from  \:  gravitational \: influence \:  \\ is \: know \: to \: be \: escape \:  velocity .  \\  \\  { the   \: formula \:  of  \: escape  \: velocity  \: we   } \\ {\: found \:  that,  \: for  \: earth, \: } \\ { it  \: is   \:   \sqrt{\frac{{2 \: G \: M} }{R}  } } \: or \:  \sqrt{2 \: g \: R}  \: . \\ \\  { \: V \: = escape  \: velocity}</p><p> \\ {G \:  = \:  gravitational  \: constant  \:} \\ {  \:  \:  \:  \:  \:  \:  \:  \:  \: is  \: 6.67408 ×  {10}^{ - 11}   {m}^{3}  {kg}^{ - 1}   {sec}^{ - 2} }</p><p></p><p> \\ {M \:  = \:  mass  \: of  \: the \:  planet}</p><p></p><p> \\ {R  \: = \:  radius \:  from  \: the   \: centre \:  of  \: gravity \: } \\ {g   \: =  \: is  \: the \:  acceleration \:  due \:  to  \: the  \: gravity  \: of  \: earth}</p><p>\\ \\  \underline\purple{The  \: escape  \: velocity  \: of  \: earth \:  is  \: } \\   \underline\purple{11  \: kilometers  \: per  \: second.}  \:  \\ \\  \underline \purple {the \: escape \: velocity \: of \: moon \:} \\  \underline \purple {is \: 2.38  \: km/s.}\\   \\  \fcolorbox{red}{white}{i \: hope \: it \: helps \: you.}

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