what is the evaluation of a^2-5a+6
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To factorise a^2–5a+6 = 0, do the following.
The product of the coefficient of x^2 and the constant is 1*6 = 6.
6 can be written as (-2)*(-3), so
we write a^2–5a+6 = 0 as
a^2–2a-3a+6 = 0
(a^2–2a)-(3a-6) = 0
a(a-2)-3(a-2) = 0
(a-3)(a-2) = 0
So the factors are (a-3) and (a-2) and the values of a = 3 or 2. Answer.
Step-by-step explanation:
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