what is the excess pressure inside a drop of mercury of radius 2mm at room temperature? Given that surface tension of mercury at room temperature is 465 dyne/cm. Also, find the pressure inside the drop, if the atmospheric pressure is 1.013 × 10^6 dyne/cm^2.
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Answer:
We know,
Excess pressure in a drop=2T/r =2×465/0.2 =4650dyne/cm²
pressure inside drop=4650+4π0.04×1.013×10^6
=5.14×10^6 dyne/cm²
Answered by
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Answer:
Excess pressure in a drop=2T/r =2×465/0.2 =4650dyne/cm²
pressure inside drop=4650+4π0.04×1.013×10^6
=5.14×10^6 dyne/cm²
Explanation:
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