What is the expansion of (3q+1)^3?
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Answer:
27q³ + 1 + 27q² + 9q
Step-by-step explanation:
Here ( 3q + 1)³ is of the form ( a + b ) ³ where a = 3q and b = 1
We know that expended form of ( a + b )³ is
a³ + b³ + 3a²b + 3ab²
Putting values of a and b we get
( 3q + 1)³ = (3q)³ + 1³ + 3(3q)²(1) + 3(3q)(1)²
= 27q³ + 1 + 27q² + 9q
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