Math, asked by patarhemant, 5 months ago

What is the expected value of the binomial distribution where n = 16 and p = 0.85?

Answers

Answered by mad210215
0

Given:

n = 16

p = 0.85

To find:

expected value =?

Step-by-step explanation:

  • In a probability distribution, the average value of possible values of a random variable, with weights given by their respective theoretical probabilities, is known as the expected value.
  • Usually, it is represented by E{x}.
  • The expected value of a binomial distribution with n trials is the average number of successes.
  • Let X be a discrete random variable with the binomial distribution with parameters n and p for some n∈N and 0≤p≤1.
  • Then the expectation of X is given by:

        E{X} = np

  • Put the given values in above equation:

        E{X} = (16) (0.85)

        E{X} = 13.6

  • Hence the expected value of the binomial distribution is 13.6 .
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