Question

what is the factor of 4y²-y+5

Answer 1

Answer:

4y²-y+5

there is no further answer

Answer 2

Given,

→ p(y) = 4y² - y + 5

To find its factors we've to equate it to zero.

→ p(y) = 0

→ 4y² - y + 5 = 0

The roots of a quadratic equation ax² + bx + c = 0 is,

→ x = [-b ± √(b² - 4ac)] / 2a

In p(y),

• x = y

• a = 4

• b = -1

• c = 5

Then,

→ x = [-b ± √(b² - 4ac)] / 2a

→ y = [-(-1) ± √((-1)² - 4 × 4 × 5)] / (2 × 4)

→ y = [1 ± √(1 - 80)] / 8

→ y = [1 ± √(-79)] / 8

→ y = (1 ± i√79) / 8

where i = √-1.

These are the roots of p(y).

So the factors are (y - (1 + i√79) / 8) and (y - (1 - i√79) / 8).