what is the factorization of a²+ab-ac-bc .
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a(a+b)-c(a+b)
(a+b)(a-c)
Answered by
0
let us rearrange the terms and take a and c as a the common factor
we get
= a
2
+ bc + ab + ac = a
2
+ ab + bc + ac
⇒a(a+b)+c(a+b)=(a+b)(a+c)
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