Math, asked by ArnavK, 11 months ago

What is the flaw in this proof?
Let a=b
a²=b²
a²=bb
a²=ab
(Subtract b² from both sides)
a²-b²=ab-b²
(a+b)(a-b)=b(a-b) (Applying Identity)
(Cancel a-b)
(a+b)=b
(b+b)=b
2b=b
2b=1b
(Cancel b)
2=1

Answers

Answered by boletoGenius

here b can only be zero ,lastly when b and a = 0

ArnavK: but 2 cannot be equal to 1

boletoGenius: only when b= 0 then only it satisfies

ArnavK: i know b = 0 but 2 cannot be equal to 1

ArnavK: there is a flaw find it

boletoGenius: a and b both zero

Answered by bhuvana3098

Let a=b

a²=b²

a²=b*b

a²=a*b

(Subtract b² from both sides)

a²-b²=ab-b²

(a+b)(a-b)=b(a-b) (Applying Identity)

(Cancel a-b)

(a+b)=b

(b+b)=b

2b=1b

2b-1b=0

b=0

ArnavK: i know b = 0 but 2 cannot be equal to 1

ArnavK: there is a flaw find it

bhuvana3098: cancel b is the flaw

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