what is the flux due to electric field E = 3 x 103 i N/C through a square of side 10cm , when it is held normal to E ?
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electric flux will be zero.
it is given that,
electric field, E = 3 × 10³ i N/C through a square of side 10cm.
we have to find electric flux through square when it is held perpendicular to E.
i.e., and between area vector and electric field is , θ = 90°.
from formula of electric flux,
Φ = E.A = |E||A|cosθ = |E||A| cos90° = 0
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Answer: el. Flux=2q÷enot
Explanation:
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