what is the focus and vertex of a parabola (y-2)^2 + 16(x-3) = 0
Answers
Answered by
5
Answer:
x
=
−
1
16
⋅
(
y
−
2
)
2
+
3
Use the vertex form,
x
=
a
(
y
−
k
)
2
+
h
, to determine the values of
a
,
h
, and
k
.
a
=
−
1
16
h
=
3
k
=
2
Step-by-step explanation:
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Answered by
5
Given : (y-2)² + 16(x-3) = 0
To Find : focus and vertex of the parabola
Solution:
(y-2)² + 16(x-3) = 0
=> (y-2)² = -16(x-3)
=> (y-2)² = 4(-4)(x-3)
comparing with
(y - k)² = 4p(x - h)
h = 3 , k = 2 , p = - 4
Vertex = ( h , k) = (3 , 2)
Focus = (h + p , k)
= ( 3 - 4 , 2)
= (-1 , 2)
Vertex is (3 ,2 )
Focus is ( -1 , 2)
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