Question

What is the following product (xroot7-3root8)(xroot7-3root8)

Answer 1

since numerator and denominator both are same , answer will be 1 .

Answer 2

$(x\sqrt7-3\sqrt8)(x\sqrt7-3\sqrt8)=7x^2-6x\sqrt{56}-72$

Step-by-step explanation:

Given : Expression $(x\sqrt7-3\sqrt8)(x\sqrt7-3\sqrt8)$

To find : What is the following product of expression ?

Solution :

Product of $(x\sqrt7-3\sqrt8)(x\sqrt7-3\sqrt8)$

Multiply term by term,

$=(x\sqrt7)\times(x\sqrt7-3\sqrt8) -3\sqrt8)\times (x\sqrt7-3\sqrt8)$

$=(x\sqrt7)\times(x\sqrt7)-(x\sqrt7)\times(3\sqrt8) -(3\sqrt8)\times (x\sqrt7)-(3\sqrt8)\times(3\sqrt8)$

$=7x^2-3x\sqrt{56}-3x\sqrt{56}-72$

$=7x^2-6x\sqrt{56}-72$

Therefore, $(x\sqrt7-3\sqrt8)(x\sqrt7-3\sqrt8)=7x^2-6x\sqrt{56}-72$

#Learn more

We observed that the product of two negative integers is a positive integer. What will be the product of three negative integers? Four negative integers? Let us observe the following examples:(–5) × [(–4) × (–3) × (–2) × (–1)] = (–5) × 24 = –120

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