What is the force between two small charged spheres having charges of 2 × 10^–7 C and 3 × 10^–7 C placed 30 cm apart in air?
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8
F= k q1 ×q2 / r²
F = 6 x 10^-14 × 9× 10^9 / 30 × 10^-2
F=54 × 10^-14 × 10^11 / 30
F = 54 ×10^-3 / 30
F= 1.8× 10^-3 N
F = 6 x 10^-14 × 9× 10^9 / 30 × 10^-2
F=54 × 10^-14 × 10^11 / 30
F = 54 ×10^-3 / 30
F= 1.8× 10^-3 N
AionAbhishek:
sorry sorry
Answered by
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Hey there !!!!!
Force exerted by two charges q₁and q₂ separated by a distance r is
F= q₁q₂/4πεr²
Here,
q₁=2*10⁻⁷C q₂=3*10⁻7C r=30cm =30*10⁻²m
1/4πε is a const value =9*10⁹
Force exerted by q₁ q₂ = 2*3*(10⁻⁷)²*9*10⁹/3*10⁻¹
=54*10⁻¹⁴*10⁹/3*10⁻¹
=18*10⁻⁵*10
=18*10⁻⁴N
Force exerted by two charges q₁and q₂ separated by a distance r is
F= q₁q₂/4πεr²
Here,
q₁=2*10⁻⁷C q₂=3*10⁻7C r=30cm =30*10⁻²m
1/4πε is a const value =9*10⁹
Force exerted by q₁ q₂ = 2*3*(10⁻⁷)²*9*10⁹/3*10⁻¹
=54*10⁻¹⁴*10⁹/3*10⁻¹
=18*10⁻⁵*10
=18*10⁻⁴N
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