What is the force constant k of a spring which is stretched
• 2 mm by a force of 4 N,
• 4 cm by a mass of 200 g?
Answers
Answered by
4
Answer:
1) K=200 N/m
2)K=50 N/m
Explanation:
in 1st case when the spring is stretched by 4 N
Kx=4
K ×2=4
so
K=2 N/mm=200 N/m
in 2nd case
gravity pulling the mass 200g (0.2 kg) downward while spring force(kx) trying to resist the gravitation pulling
so
Kx=mg
K×4=0.2×10
k=0.5 N/cm=50 N/m
Answered by
0
Answer:
k = 200n/m
k=50 n/m
Explanation:
kx=4
k X 2 = 4
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