Question

What is the force in pounds exerted upwards on a piston with a diameter of 4 inches if a gauge indicates the internal pressure in the cylinder is 1000 psi?​

Answer 1

Answer:

Preasure = Force / area

Preasure = Force / pi*r2

1000 = f / 3.14*2^2

1000 = f / 12.566

f = 12566 lbs of force.

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Answer 2

Answer:

The force exerted upwards on pistol is 54123.84 Newton

Step-by-step-explanation:

Diameter of piston = 4 inches ( 1 inch equal 0. 025)

So, diameter is 0.1 meter

Radius of pistol ( r) = 0.1/2 = 0.05 meter

Area of the piston = $\pi$.r²

                        = 3.14×(0.05)²

                        = 3.14 × 2.5×10^-3

                        = 7.85×10^-3 Sq. m

pressure in the cylinder = 1000 psi = 1000×6894.757 (1 PSI = 6894.757 Pascal)

= 6894757 Pascal

Pressure = Force/Area

Force = Pressure×area

F = 6894757×7.85×10^-3

F = 54123.84 Newton

Therefore the force exerted on the cylinder of area 7.85×10^-3 Sq. meter and having pressure 6894757 Pascal is 54123.84 Newton.

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