Question

what is the formula of arithmetic progression​

Answer 1

Answer:

Tn=a+(n-1)d

Sn=n/2(2a+(n-1)d)

Sn=n/2(a+l)

Answer 2

The formula of arithmetic progression is:

1)a,a+d,a+2d,a+3d and so on.

2)Tn=a+(n-1)d

3)Sn=n/2(2a+(n-1)d)

4)Sn=n/2(2a+l)

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