What is the formula of compound in which the element y forms hcp lattice and atoms of x occupy 1/3rd of octahedral voids?
Answers
Answered by
15
y=6(hcp)
x=1/3×4=4/3
FORMULA=x:y
=4/3:6
=4:18
X4Y18
x=1/3×4=4/3
FORMULA=x:y
=4/3:6
=4:18
X4Y18
Answered by
0
XY3 .
Given:
Element 'y' forms hcp lattice & atoms of x occupy 1/3 rd of the octahedral voids.
To Find:
The formula of that compound.
Solution:
=) Y forms hcp lattice = 6atoms
=) X occupy 1/3octahedral voids.
Octahedral == n ( here value of n is : 6 )
Thus,
X = 1/3 x 6 = 2
Which gives us formula: X2Y6
On simplifying we get: XY3
Hence, formula of that compound is : XY3.
#SPJ3
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