Question

What is the formula of Compound Interest

Answer 1

Compound interest = final amount-original amount

Answer 2

$\huge{\blue{\bold{Solution}}}$

=>Amount after n years is given by

$a = p \: {(1 +\frac{r}{100 })} ^{n}$

=>Compound interest = (amount)–(principal)..

=>If the rates be p%, q% and r % during the 1st , 2nd and 3rd year respectively ...then ,

$amount \: after \: 3 \: years \:$
$= p(1 + \frac{p}{100} )(1 + \frac{q}{100})(1 + \frac{r}{100} )$

=>If the principal = Rs . P , rate = R% per annum and the time = n years , then

[i] amount after n years ( compounded annually)

$= rs. \: p(1 + \frac{r}{4 \times 100} )^{n}$

[ii] amount after n years ( compounded half yearly )

$= rs. \: p \: (1 + \frac{r}{2 \times 100} ) \: ^{2n} ...$

[iii] amount after n years ( compounded quarterly)

$= rs. \: p \: (1 + \frac{r}{4 \times 100}) ^{4n} .....$

=>If the present population of a place is P and it's increase at the rate of R% per annum ..then,

[I] Population after n years ..that is

$= p(1 + \frac{r}{100} )^{n..}$

[II] population after n years ago

$= \frac{p}{(1 + \frac{r}{100}) ^{n....} }$

=> If the present population of a place is P and it decrease at R % per annum , then

Population after n years
$= p(1 - \frac{r}{100} ) ^{n}$

=>Suppose If the present population value of a machine is Rs. P and it depreciates at the rate of R% per annum then it's value after n years ...

$= rs.p \: (1 - \frac{r}{100})^{n}$

THESE ARE THE FORMULA OF CALCULATING COMPOUND INTEREST .....

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