Question

what is the formulas of trigonometry

Answer 1

HOLA friend!!
Rajdeep here....

What are the formulas of trigonometry?
Here are some for you:

Let B be the base and P be the Perpendicular and H be the hypotenuse and A be the angle, then:

sin A = P/H
cos A = B/H
tan A = P/B

cosec A = H/P
sec A = H/B
cot A = B/P


Now, the square formulas:
1. sin²A + cos²A = 1
sin²A = 1 - cos²A
cos²A = 1 - sin²A


2. sec²A - tan²A = 1 
sec²A = 1 + tan²A
tan²A = sec²A - 1

3. cosec²A - cot²A = 1
cosec²A = 1 + cot²A
cot²A = cosec²A - 1



THANKS!

Answer 2

ApplyingPythagoras theoremfor the given right-angled theorem, we have:\((Perpendicular)^{2} + (Base)^{2} = (Hypotenuese)^{2}\)\(\Rightarrow (P)^{2} + (B)^{2} = (H)^{2}\)The Trigonometric properties are given below:S.noPropertyMathematical value1\(\sin A\)\(\frac{P}{H}\)2\(\cos A\)\(\frac{B}{H}\)3\(\tan A\)\(\frac{P}{B}\)4\(\cot A\)\(\frac{B}{P}\)5\(cosec A\)\(\frac{H}{P}\)6\(\sec A\)\(\frac{H}{B}\)Relation Between Trigonometric Identities:S.noIdentityRelation1\(\tan A\)\(\frac{\sin A}{\cos A}\)2\(\cot A\)\(\frac{\cos A}{\sin A}\)3\(cosec A\)\(\frac{1}{\sin A}\)4\(\sec A\)\(\frac{1}{\cos A}\)Trigonometric Identities:1.\(\sin^{2}A + \cos^{2}A = 1\)1.\(\tan^{2}A + 1 = \sec^{2}A\)1.\(\cot^{2}A + 1 = cosec^{2}A\)