Question

What is the free energy change if the ratio of the concentrations of the products to the concentrations of the reactants is 22.3, and the temperature is 37.0 °C? ?G°\' for the reaction is –16.7 kJ/mol

Answer 1

Given info : The ratio of the concentrations of the products to the concentrations of the reactants is 22.3, and the temperature is 37.0 °C and ∆G° for the reaction is -16.7 kJ/mol.

To find : The free energy change is ...

solution : temperature, T = 37 + 273 = 310K

ratio of the products to the reactants, Q = 22.3

standard Gibbs free energy, ∆G° = -16.7 kJ/mol

using formula,

∆G = ∆G° + RTlnQ

⇒∆G = -16.7 kJ/mol + 25/3 J/mol/K × 310K ln(22.3)

= -16.7 kJ/mol + 8020.18 J/mol

= -16.7 kJ/mol + 8.02 kJ/mol

= -8.68 kJ/mol

Therefore the free energy change for the reaction is -8.68 kJ/mol.