What is the freezing point of radiator fluid that is 50% antifreeze by mass? kf for water is 1.86 ∘c/m?
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Ethylene glycol, the primary ingredient in antifreeze, has the chemical formula C2H6O2 . The radiator fluid used in most cars is a half-and-half mixture of water and antifreeze.
Take 1000 g of solution; then you would have 500 g ethylene glycol and 500 g water.
Mol. mass C2H6O2 = 2(12) + 6(1) + 2(16) =62 g/mole
Molality = total C2H6O2 in solution / (mol. mass)(kg water)
Molality = 500g / (62 g/mole)(0.500 kg) =16.1 m
delta T = Kbp X m = (0.512 C / m)(16.1 m) = 8.24 C
So the boiling point = 100 C + 8.24 C = 108.24 C
F = 9/5C - 32 = 9/5(108.24) -32 = 226.8 F
Take 1000 g of solution; then you would have 500 g ethylene glycol and 500 g water.
Mol. mass C2H6O2 = 2(12) + 6(1) + 2(16) =62 g/mole
Molality = total C2H6O2 in solution / (mol. mass)(kg water)
Molality = 500g / (62 g/mole)(0.500 kg) =16.1 m
delta T = Kbp X m = (0.512 C / m)(16.1 m) = 8.24 C
So the boiling point = 100 C + 8.24 C = 108.24 C
F = 9/5C - 32 = 9/5(108.24) -32 = 226.8 F
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