Question

What is the frequency of photon , whose momentum is 1.1×10^-23?

Answer 1

Given:

The momentum of a photon is 1.1×10^-23

To find:

What is the frequency of photon , whose momentum is 1.1×10^-23?

Solution:

Let "p" be the momentum of the photon

we use the formula,

p = mc

where, m = mass of the photon

Now consider,

E = mc² ....(1)

where E is the energy of photon and c is the speed of light.

E = h × f  ......(2)

where f is the frequency of the photon.

using equations (1) and (2), we get,

mc² = h × f

⇒ m = hf/c²  .......(3)

we have,

p = m × c

substituting the value of m (3) in above equation we get,

p = hf/c² × c

p = hf/c

⇒ f = pc/h

c = 3 × 10^8 and h = 6.623 × 10^{-34}

given, p = 1.1 × 10^{-23}

∴ f = (1.1 × 10^{-23}) × (3 × 10^8) / (6.623 × 10^{-34})

upon solving, we get,

f = 0.498 × 10^{19}

∴ f = 4.98 × 10^{18} Hz.

Hence the frequency of a photon.

Answer 2

Answer:

Explanation:

Momentum=1..1*10^-23

Energy=Momentum*Speed of light

Energy=3.3*10^-15J

hn=Energy,where h is Planck constant,n is frequency, apply this formula, you will get the answer