Question

What is the GCF of 48m5n and 81m2n2?

Answer 1

Answer:

$G.C.F=3m^2n$

Step-by-step explanation:

Concept used:

The greatest common factor of two polynomial is a polynomial of highest degree that divides both the polynomials.

$48m^5n=2*2*2*2*3*m^5*n$

$\implies\:48m^5n=2^4*3*m^5*n$

$81m^2n^2=3*3*3*3*m^2*n^2$

$\implies\:81m^2n^2=3^4*m^2*n^2$

Now,

$G.C.F=3*m^2*n$

$G.C.F=3m^2n$

Answer 2

The greatest common factor of $48m^5n$ and $81m^2n^2$ is $3m^2n$.

Step-by-step explanation:

Given : Numbers $48m^5n$ and $81m^2n^2$

To find : What is the GCF of numbers ?

Solution :

Factorizing the numbers,

$48m^5n=2\times2\times2\times2\times 3\timesm\times m\times m\times m\times m\times n$

$81m^2n^2=3\times3\times3\times3\times m\times m\times n\times n$

GCF is the greatest common factor,

$GCF(48m^5n,81m^2n^2)=3\times m\times m\times n$

$GCF(48m^5n,81m^2n^2)=3m^2n$

Therefore, the greatest common factor of $48m^5n$ and $81m^2n^2$ is $3m^2n$.

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