What is the general form of the equation for the circle?
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x-h)^2 + (y-k)^2 = r^2 where r is the radius of the circle,
and h,k are the coordinates of its center.
(x-3)^2+(y-8)^2 = 25
x^2-6x+9 +y^2-16x+64 = 25
x2 + y2 + 6x + 16y + 48 = 0
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(x-h)^2+(y-k)^2=r^2.
(x-3)^2+(y-8)^2=25
X+9-6x+y+64-16y-25=0
x^2+y^2-6x-16y+48=0
(x-3)^2+(y-8)^2=25
X+9-6x+y+64-16y-25=0
x^2+y^2-6x-16y+48=0
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