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What is the gravitational potential at a point when the gravitational field distance 8,000 km from the center of the Earth is 6N/m?

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Answer 1

r = 8000km = 8 × 10^6 m

Gravitational field = 6 N/kg

$\Rightarrow \frac{GM}{ {r}^{2} } = 6$

We need to find gravitational potential.

$gravitational \: potential = \frac{GM}{ {r}} \\ \\ = \frac{GM}{ {r}^{2} } \times r \\ \\ = 6 \times 8 \times {10}^{6} \: \: Nm/kg \\ \\ = 4.8 \times {10}^{7} \: \: J/kg$

Answer 2

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r = 8000km = 8 × 10^6 m

Gravitational field = 6 N/kg

$\Rightarrow \frac{GM}{ {r}^{2} } = 6$

We need to find gravitational potential.

$gravitational \: potential = \frac{GM}{ {r}} \\ \\ = \frac{GM}{ {r}^{2} } \times r \\ \\ = 6 \times 8 \times {10}^{6} \: \: Nm/kg \\ \\ = 4.8 \times {10}^{7} \: \: J/kg$

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