Question

what is the great amount of NH3 moles that can be produced with 3.2 moles of N2 and 5.4 moles of H2, which is limiting reagent and excess reactant

Answer 1

Answer:

N2 and H2 respectively

Explanation:

the answer of this question is

first we have to balance this equation -

2NH3 product formed by N2 and 3H2

then the moles of N2 is 3.2 which is limiting reagent and have 2 atoms while 3H2 have 3 molecules and 5.4 moles which is excess reagent.