Question

what is the greatest number that can divides 89, 112 and 158 when 3 is added to them?

Answer 1

Hi ,

Add 3 to each number we get

89 + 3 = 92

112 +3 = 115

158 + 3 = 161

Express the numbers into product primes

92 = 2 × 2 × 23

115 = 5 × 23

161 = 7 × 23

HCF ( 92 , 115 , 161 ) = 23

Therefore ,

23 is the required greatest number

which can divide 92 , 115 and 161.

I hope this helps you.

:)

Answer 2

Answer:

Hi mate, 23 is your answer. How?

Step-by-step explanation:

Greatest number that divides 89,112 and 158 when 3 is added to it =

89+3= 92

112+3= 115

158+3= 161

Greatest number means HCF.

So now we have to find the HCF of 92, 115 and 161.

Factors of 92= 1, 2, 4, 23, 46, 92

Factors of 115= 1, 5, 23, 115

Factors of 161= 1, 7, 23, 161

Common factor between them= 1 and 23

Greatest factor= 23

So, 23 is the greatest number that can divides 89, 112 and 158 when 3 is added to them.

Pls mark me as the brainliest if it is helpful to you. Hope it helps.

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