What is the greatest number that divides 37,50 and 123 leaving remainder 1,2 and 3 respectively
a) 9
b) 10
c) 15
d) 12
Answers
Answered by
1
D) 12
37/12 gives the remainder 1 (12x3=36) (37-36=1)
50/12 gives the remainder 2. (12x4=48) (50-48=2)
123/12 gives the remainder 3. (12x10=120) (123-129=3)
37/12 gives the remainder 1 (12x3=36) (37-36=1)
50/12 gives the remainder 2. (12x4=48) (50-48=2)
123/12 gives the remainder 3. (12x10=120) (123-129=3)
Answered by
0
Answer:
37−1=36,50−2=48
123−3=120
HCF of 36, 48 and 120=12
∴ required number =12.
Similar questions