Question

What is the half cell potential of Zn/Znso4 (0.01M) at 25°c ?. E°zn/zn^2+ = -0.76V​

Answer 1

Given,

• n = 2

• $E_0_{oxid}=0.763 \:V$

We know,

$E_0_{oxi}=E_0_{red}-\dfrac{0.0591}{2}log[Zn^{2+}]$

$\implies E_0_{oxi}=0.763-\dfrac{0.0591}{2}log[0.01]$

$\implies E_0_{oxi}=0.763-(-0.0591)$

$\implies E_0_{oxi}=0.8221\:V$

$\boxed{\displaystyle\sf{E_0_{oxi}=0.8221\:V}}$

Answer 2

Answer:

Hi mate

mate Here is your answer

mate Here is your answer Hope it helps

mate Here is your answer Hope it helps Sorry for bad handwriting

mate Here is your answer Hope it helps Sorry for bad handwriting Take care yourself

mate Here is your answer Hope it helps Sorry for bad handwriting Take care yourself Keep smiling