Math, asked by anshavalayath, 8 months ago

what is the HCF of 321, 428, 535?

Answers

Answered by gouri3635nms
5

Answer:

The factors of 321 are: 1, 3, 107, 321

The factors of 428 are: 1, 2, 4, 107, 214, 428

The factors of 535 are: 1, 5, 107, 535

Then the greatest common factor is 107.

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Answered by sshailshetty
2

Answer:• We have to find the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively.

Now..

=> 328 - 7 = 321

=> 436 - 8 = 428

=> 544 - 9 = 535

Now.. we have to find the H.C.F. of 321, 428, 535

• HCF of 321 = 3 × 107

• HCF of 428 = 2 × 2 × 107

• HCF of 535 = 5 × 107

107 is common in 321, 428 and 535.

So, HCF is 107

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107 is the greatest number that will divide 328, 436, and 544 leaving remainder 7, 8 and 9 respectively

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