What is the hcf of 4052'12570
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You can find it by Euclid's division algorithm method or you can refer to NCERT chapter 1 examples.....
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Answer:
4
Step-by-step explanation:
Use Euclid's division algorithm
so divide 12570 by 4052
so we get a remainder of 420
divide 12570 by 420
we get a remainder of 272
divide 420 by 272
we get a remainder of 148
divide 272 by 148
we get a remainder of 124
divide 148 by 124
we get a remainder of 24
divide 124 by 24
we get a remainder of 4
divide 24 by 4
we get a remainder of 0
so it is divisible by 4 its HCF is 4
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