Question

What is the HCF of 8(x^5-x^3+x) and 28(x^6+1) ​

Answer 1

Answer:

28(x6 + 1) = 28(x2)3 + 13 = 7×4×(x2 + 1)(x4 + 1 - x2)

= 7(x2 + 1)×4(x4 + 1 - x2) 

Also, 8 (x5 - x3 + x) = 2x × 4(x4 + 1 - x2)

So, HCF = 4(x4 + 1 - x2)