Question

what is the HCF of two consecutive even number

a)1
b)2
c)4
d)8​

Answer 1

Answer:

HCF of any two consecutive even numbers is 2.

Step-by-step explanation:

Let us consider two consecutive numbers 2b and (2b+2).

2b = 2 × b

2b + 2 = 2(b + 2) = 2 × (b + 2)

HCF of (2b, 2b+2) = 2

2n,(2n+2) are two consecutive even Numbers.

2n = 2×n

2n+2 = 2(n+2) = 2×(n+2)

HCF(2n,2n+2)= 2

Let us verify the above statment.

To find HCF of 2, 4

Let us find the Highest Common Factor of 2, 4

We get the factors as factors of 2 =2

Factors of 4 =2 x 2

HCF of (2, 4) = 2

Answer 2

Answer:

HCF of two consecutive even

number is 2.