what is the highest and lowest resistance that can be secured by combination of 4 coils of resistance 4 ohm 8ohm 12ohm 24ohm
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Answered by
3
Answer:
highest is 24+12+8+4=48ohm
lowest=1/24+1/12+1/8+1/4=1/2
Answered by
4
Answer:
The highest resistance that can be secured by combination of 4 coils is by connecting them in series combination
∴ total resistance = 4 + 8 + 12 + 24
= 48 Ω
lowest resistance that can be secured by combination of 4 coils is by connecting them in parallel combination.
total resistance = 1/R₁ + 1/R₂ + 1/R₃ + 1/R₄
= 1/4 + 1/8 + 1/12 + 1/24
= 6 + 3 + 2 + 1 /24
= 1/2
∴ total resistance = 2Ω
hope its helpful
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