what is the highest and the lowest total resistance which can be obtained by combining 8 resistors of 4 ohm each
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heighest can be achieved when they are connected in series-
Rs= R1+R2+_ _+ Rn
therefore it is 4+4+4+4+4+4+4+4=4*8=32ohm.
lowest when the are connected in parallel
1/RP = 1/R1+1/R2+....+1/Rn
therefor it is= 1/4 multiplied by 8=8/4 = 1/2=0.5ohm
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