WHAT IS THE HIGHEST ,THE LOWEST RESISTANCE THAT CAN BE SECURED BY COMBINATION OF FOUR COILS OF RESISTANCE 4 ,8,12,24
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Explanation:
What is (a) the highest, (b) the lowesttotal resistance that can be secured by combinations of four coils of resistance 4 Ω, 8 Ω, 12 Ω, 24 Ω? R = 4 + 8 + 12 + 24 = 48 Ω.
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Ans: Given resistances R1 =4 Ω, R2=8 Ω, R3=12Ω, and R4=24Ω.
(a) If these coils are connected in series, then the equivalent resistance will
be the highest, as R=R1+R2+R3+R4
∴ R=4+8+12+24 = 24Ω
(b) If these coils are connected in parallel, then the equivalent resistance will be the lowest, given by
⇒R=2 Ω
∴ 2 Ω is the lowest total resistance.
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