What is the hybridisation of Xe in XeO2F2??
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Hybridization of the compound can be found by using the formula that is mentioned as follows:
Hybridization number= (no of valence electrons in central atom + number of mono valent atoms directly attached))/2
In the above mentioned chemical compound, Xe is the central atom and the valence electrons are 8 in number.
Number of monovalent atoms attached directly to the fluorine atoms are 2. Therefore hybridization number = (8+2)/2=5
The number 5 means that there are 5 hybrid orbitals. It is possible only for sp3d configuration.
Hence the substance is equipped with Sp3d hybridization.
Hybridization number= (no of valence electrons in central atom + number of mono valent atoms directly attached))/2
In the above mentioned chemical compound, Xe is the central atom and the valence electrons are 8 in number.
Number of monovalent atoms attached directly to the fluorine atoms are 2. Therefore hybridization number = (8+2)/2=5
The number 5 means that there are 5 hybrid orbitals. It is possible only for sp3d configuration.
Hence the substance is equipped with Sp3d hybridization.
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