Question

What is the Hybridization of ClF3 molecule ? Explain.

Answer 1

it's hybdrisation is sp³d...... bcoz the central atom I,Cl has 4 lone pairs for which it requires 2 hybrid orbitals and to form 3 bonds with 3 atom of F it requires 3 more hybrid orbitals.... so total no. of hybrid orbitals =5......
hope it helps

Answer 2

The Hybridization of $ClF_3$ molecule is $sp_3d$

Explanation:

Formula used  :

$\text{Number of electrons}=\frac{1}{2}[V+N-C+A]$

where,

V = number of valence electrons present in central atom

N = number of monovalent atoms bonded to central atom

C = charge of cation

A = charge of anion

Now we have to determine the hybridization of the $ClF_3$ molecule.

$\text{Number of electrons}=\frac{1}{2}\times [7+3]=5$

Bond pair electrons = 3

Lone pair electrons = 5 - 3= 2

The number of electrons are 5 that means the hybridization will be $sp_3d$ and the electronic geometry of the molecule will be trigonal pyramidal.

But as there are three atoms around the central chlorine atom, the fourth and fifth position will be occupied by lone pair of electrons. The repulsion between lone and bond pair of electrons is more and hence the molecular geometry will be T- shaped.

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