Question

What is the increase in the area of the figure is a square and the sides are increased by 20% each?

Answer 1

Step-by-step explanation:

let the side of the square be x

it's area will be x^2

if side is increased 20%

x + 20% of x

$= x + \frac{20}{100} \times x \\ = x + \frac{x}{5} \\ = \frac{5x + x}{5} \\ = \frac{6x}{5} \\ \\ area \: will \: be \: \\ {( \frac{6x}{5}) }^{2} = \frac{36 {x}^{2} }{25}$

area of square will increase by 36/25

hope you get your answer

Answer 2

Step-by-step explanation:

Let the side of the square be 'x'.

We know that Area = x^2.

Given that side of a square is increased by 20%.

=> Length of each side = x + 20% of x = 120x/100 = (6/5)x

New area = (6x/5)^2 = (36x^2/25)

Now,

Increase in area = (36x^2/25) - x^2

                           = (36x^2 - 25x^2)/25

                           = 11x^2/25

So, the % increase in area = (11x^2/25) * (100/x^2)

= > 1100/25

= > 44.

Therefore, Area is increased by 44%.

Hope this helps!