Question

what is the integral of
${e}^ - { \frac{x}{6} }$
​

Answer 1

The final answer is $-6 \ e^\frac{-x}{6}$

Step-by-step explanation:

$\ Given \ value:\\\\ e^\frac{-x}{6} \\\\ \ find= ? \\\\ \ intigration= ? \\\\ \ Solution: \\\\ \int \limits e^\frac{-x}{6} \, dx \\\\\ let \ t = \frac{-x}{6}\\\\\ differentiation \ formula: \\\\ \ x^n = nx^n-1 \\\\ \ differentiation : \\\\t = \frac{-x}{6}\\\\t = \frac{-x^1}{6}\\\\\ x^1 = 1x^1-1 \\ \rightarrow 1\times x^0 \\\\ \rightarrow 1\\\\ \frac{dt}{dx} = \frac{-1}{6} \\\\\int \limits e^\frac{-x}{6} \, dx \\\\-6 \ e^\frac{-x}{6} + c\\\\\ where \ c\ is \ constant.$

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