Question

what is the interior angle of a regular octagon of side length 2 cm​

Answer 1

Given:

Side length of octagon $=2cm$

To find:

The interior angle of a polygon is

$(n-2) \times \frac{180^{0} }{n}$

$n=$ number of sides

Interior angle of a regular octagon$=180^{0} -$Exterior Angle

Step-by-step explanation:

Regular octagon has $8$ sides.

thus,$n=8$

Interior angle $=(n-2) \times \frac{180^{0} }{n}$

                      $=(8-2) \times \frac{180^{0} }{8}$

                      $=6 \times \frac{180^{0} }{8}$

                      $=\frac{3\pi }{4}$

The interior angle is $=\frac{3\pi }{4}$